Решите и найдите x
[tex] \frac{(y - 4)(y + 4)}{ {12y}^{2} + 12y } = 0[/tex]
[tex] \frac{(y - 4)(y + 4)}{ {12y}^{2} + 12y } = 0[/tex]
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Ответ: -4 ; 4
[tex]\frac{(y - 4)(y + 4)}{ {12y}^{2} + 12y } = 0 \\ (y - 4)(y + 4) = 0 \\ {y}^{2} - 16 = 0 \\ {y}^{2} = 16 \\ y = 4 \: \: \: \: \: \: \: \: y = - 4 \: \: \: \: \: [/tex]