розв'яжіть рівняння

[tex] \sqrt{2x + 8} = x[/tex]
[tex] \sqrt[3]{x - 1} = 2[/tex]
[tex] \sqrt{ {x }^{2} - 36 } = \sqrt{2x - 1} [/tex]
[tex] \sqrt{x + 5} - \sqrt{8 - x} = 1[/tex]


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