Ответ:

8

Объяснение:

[tex]16 = t(t - 6) \\ 16 = {t}^{2} - 6t \\ - {t}^{2} + 6t + 16 = 0 \\ {t}^{2} - 6t - 16 = 0 \\ d = 6 {}^{2} + 4 \times 1 \times 16 = 36 + 64 = 100 \\ t1 = \frac{6 + \sqrt{100} }{2 \times 1} = \frac{6 + 10}{2} = \frac{16}{2} = 8 \\ t2 = \frac{6 - \sqrt{100} }{2 \times 1} = \frac{6 - 10}{2} = - \frac{4}{2} = - 2[/tex]