Ответ: (x-1)/(x-3)
[tex]\frac{(x^{2} -4x+3)}{(x-3)^{2} } \frac{(x - 3)(x - 1)}{ {(x - 3)}^{2} } = \frac{x - 1}{x - 3} \\ [/tex]
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Ответ: (x-1)/(x-3)
[tex]\frac{(x^{2} -4x+3)}{(x-3)^{2} } \frac{(x - 3)(x - 1)}{ {(x - 3)}^{2} } = \frac{x - 1}{x - 3} \\ [/tex]