решите неравенство
[tex] \frac{3x - 1}{2} - \frac{x - 2}{3} < \frac{x - 3}{4} [/tex]
[tex] \frac{3x - 1}{2} - \frac{x - 2}{3} < \frac{x - 3}{4} [/tex]
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Пошаговое объяснение:
[tex]\frac{3x-1}{2}-\frac{x-2}{3} < \frac{x-3}{4}\ |*12\\ 6*(3x-1)-4*(x-2) < 3*(x-3)\\ 18x-6-4x+8 < 3x-9\\ 11x < -11\ |:11\\x < -1.[/tex]
Ответ: x∈(-∞;-1).