Объяснение:
[tex]2*sin\alpha +sin^2\alpha +cos^2\alpha =1\\2*sin\alpha +1=1\\2*sin\alpha =0\ |:2\\sin\alpha =0\\\alpha =\pi n,\ \ \ \ n \in \mathbb Z.[/tex]
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Verified answer
Объяснение:
[tex]2*sin\alpha +sin^2\alpha +cos^2\alpha =1\\2*sin\alpha +1=1\\2*sin\alpha =0\ |:2\\sin\alpha =0\\\alpha =\pi n,\ \ \ \ n \in \mathbb Z.[/tex]