Ответ:
[tex]\dfrac{7k^3(k-a)^2}{12(a-k^4)}[/tex]
Объяснение:
[tex]\dfrac{63k^4(k-a)^2}{108k(a-k^4)} \div\dfrac{9k}{9k}=\dfrac{7k^3(k-a)^2}{12(a-k^4)}[/tex]
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Ответ:
[tex]\dfrac{7k^3(k-a)^2}{12(a-k^4)}[/tex]
Объяснение:
[tex]\dfrac{63k^4(k-a)^2}{108k(a-k^4)} \div\dfrac{9k}{9k}=\dfrac{7k^3(k-a)^2}{12(a-k^4)}[/tex]