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решение смотри на фотографии

[tex]\displaystyle\bf\\4x^{2} -4x-3=0\\\\D=(-4)^{2} -4\cdot 4\cdot(-3)=16+48=64=8^{2} \\\\\\x_{1} =\frac{4-8}{8} =\frac{-4}{8} =-0,5\\\\\\x_{2}= \frac{4+8}{8} =\frac{12}{8} =1,5\\\\\\Otvet: \ -0,5 \ \ ; \ \ 1,5[/tex]