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agrabar6
@agrabar6
May 2023
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[tex]\lim_{n \to \infty} (1+\frac{1}{3} +\frac{1}{9}+...+\frac{1}{3n} )[/tex]
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s4ndstrm
решение во вложении
====================
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agrabar6
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решение во вложении
====================