решите уравнение:
[tex] - 8 \frac{7}{16} c + 10 \frac{19}{24}c - 3 \frac{3}{8} c = - 3\frac{1}{16} [/tex]
[tex] - 8 \frac{7}{16} c + 10 \frac{19}{24}c - 3 \frac{3}{8} c = - 3\frac{1}{16} [/tex]
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Ответ:
3
Пошаговое объяснение:
[tex]-8\frac{7}{16}c+10\frac{19}{24}c-3\frac{3}{8}c =-3\frac{1}{16} \\-8\frac{21}{48}c+10\frac{38}{48}c-3\frac{18}{48}c=-3\frac{3}{48}\\ \frac{-405c+518c-162c}{48} =-\frac{147}{48} \\-405c+518c-162c=-147\\113c-162c=-147\\-49c=-147\\49 c=147\\c=\frac{147}{49}=3[/tex]