[tex] {x}^{2} - 8x + 15 = 0[/tex]
[tex] \frac{(x + 1) { }^{2} }{12} - \frac{1 - {x}^{2} }{24} = 4[/tex]
[tex] {x}^{2} - \frac{13}{4} x + 0.75 = 0[/tex]
[tex](8x - 1)(2x - 3) - (4x - 1 {)}^{2} = 38[/tex]
[tex] \frac{1}{3} (15x - 1)(1 + 15x) = \frac{8}{3} [/tex]
[tex](6 - x)(x + 6) - ( x - 11)x = 36[/tex]
[tex]9 {x}^{2} - \frac{(12x - 11)(3x + 8)}{4} = 1[/tex]
помогите пожалуйста.




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