Решить тригонометрические неравенства.

1. [tex]sinx\ \textgreater \ \frac{1}{2}[/tex]

2.[tex]cosx\ \textless \ -\frac{\sqrt{2}}{2}[/tex]

3.[tex]\sqrt{2} sin(\frac{\pi}{2} -2x)\ \textgreater \ 1[/tex]

4.[tex]2cos(\frac{3\pi }{2}+3x )\leq -\sqrt{2}[/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.