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lozas3169
@lozas3169
June 2023
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Способы преобразования графиков функции
Помогите решить эти функции пожалуйста!!!!
1.
[tex]y = x^{2} + 2[/tex]
2.
[tex]y = (x + 8)^{2} [/tex]
3.
[tex]y = 2 \sin x[/tex]
4.
[tex]y = \sin \: x + 2[/tex]
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Answers & Comments
jasminzakupbek
1) (0,2)
2
2)y=x. + 16x +64
3)y’=2cos(x)
4) y’ =cos(x)
1 votes
Thanks 0
lozas3169
можешь начертить пожалуйста?
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Answers & Comments
2
2)y=x. + 16x +64
3)y’=2cos(x)
4) y’ =cos(x)