1)
[tex] \frac{2 \sqrt{3} + \sqrt{3} }{ \sqrt{3} } = \frac{3 \sqrt{3} }{ \sqrt{3} } = 3[/tex]
2)
[tex] \frac{6 - \sqrt{6} }{ \sqrt{18} - \sqrt{3} } = \frac{ \sqrt{6}( \sqrt{6} - 1) }{ \sqrt{3}( \sqrt{6} - 1)} = \frac{ \sqrt{6} }{ \sqrt{3} } = \sqrt{ \frac{6}{3} } = \sqrt{2} [/tex]
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Answers & Comments
1)
[tex] \frac{2 \sqrt{3} + \sqrt{3} }{ \sqrt{3} } = \frac{3 \sqrt{3} }{ \sqrt{3} } = 3[/tex]
2)
[tex] \frac{6 - \sqrt{6} }{ \sqrt{18} - \sqrt{3} } = \frac{ \sqrt{6}( \sqrt{6} - 1) }{ \sqrt{3}( \sqrt{6} - 1)} = \frac{ \sqrt{6} }{ \sqrt{3} } = \sqrt{ \frac{6}{3} } = \sqrt{2} [/tex]