Verified answer

Ответ:

x ∈ (-∞;[tex]\frac{6}{11}\\[/tex]]

Объяснение:

[tex](4x-3)^2+(3x+2)^2\geq(5x+1)^2\\(16x^2-24x+9)+(9x^2+12x+4)\geq25x^2+10x+1\\16x^2-24x+9+9x^2+12x+4\geq25x^2+10x+1\\25x^2-12x+13\geq25x^2+10x+1\\25x^2-12x+13-25x^2-10x-1\geq0\\-22x+12\geq0\\-22x\geq-12\\x\leq\frac{-12}{-22} \\x\leq \frac{6}{11}\\[/tex]