[tex]\frac{a-1}{a(a-5)} +\frac{1}{5-a} = \frac{a-1}{a(a-5)} +\frac{1}{-(a-5)}=\frac{a-1}{a(a-5)} -\frac{1}{a-5}=\frac{a-1-a}{a(a-5)} = \frac{-1}{a(a-5)} = -\frac{1}{a^{2} -5a}[/tex]
[tex]\frac{a-1}{a(a-5)} -\frac{1}{5-a} = \frac{a-1}{a(a-5)} -\frac{1}{-(a-5)} = \frac{a-1}{a(a-5)} +\frac{1}{a-5}= \frac{a-1+a}{a(a-5)}= \frac{2a-1}{a^{2} -5a)}[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\frac{a-1}{a(a-5)} +\frac{1}{5-a} = \frac{a-1}{a(a-5)} +\frac{1}{-(a-5)}=\frac{a-1}{a(a-5)} -\frac{1}{a-5}=\frac{a-1-a}{a(a-5)} = \frac{-1}{a(a-5)} = -\frac{1}{a^{2} -5a}[/tex]
[tex]\frac{a-1}{a(a-5)} -\frac{1}{5-a} = \frac{a-1}{a(a-5)} -\frac{1}{-(a-5)} = \frac{a-1}{a(a-5)} +\frac{1}{a-5}= \frac{a-1+a}{a(a-5)}= \frac{2a-1}{a^{2} -5a)}[/tex]