Verified answer

Ответ:

[tex]4 \frac{1}{48} [/tex]

[tex] \frac{7 \frac{1}{4} + 5 - 2 \frac{1}{3} + 6 \frac{1}{6} }{4} = \frac{16 + \frac{1}{4} - \frac{1}{3} + \frac{1}{6} }{4} = 4 + \frac{ - \frac{1}{12} + \frac{1}{6} }{4} = 4 + \frac{1}{12 \times 4} = 4 \frac{1}{48} [/tex]