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Distrrict
@Distrrict
July 2022
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Найдите точку максимума функции
y=[tex] \frac{x^3}{3} [/tex]-9x-7
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876234456
Y=1/3* x^3 - 9x - 7
y ' = 1/3 *3x^2 - 9 = x^2 - 9
y ' = 0
x^2 - 9 = 0
( x - 3)( x + 3) =0
x = ± 3
+ - +
------------------*----------------*--------------->
( - 3) (3)
т. max ==> x = - 3
1 votes
Thanks 1
MrCalling
Производная
нашли стационарные точки, смотрим таблицу во вложении
ответ -3
2 votes
Thanks 1
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Answers & Comments
y ' = 1/3 *3x^2 - 9 = x^2 - 9
y ' = 0
x^2 - 9 = 0
( x - 3)( x + 3) =0
x = ± 3
+ - +
------------------*----------------*--------------->
( - 3) (3)
т. max ==> x = - 3
нашли стационарные точки, смотрим таблицу во вложении
ответ -3