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lllvvvnnn98
@lllvvvnnn98
July 2022
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Найдите область значений выражения [tex] \frac{2x^{2}-x-1 }{ x^{2} +x-2} [/tex]
а) y≠2 б) y≠3 в) y≠1 г) другой ответ
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kirichekov
Verified answer
2x²-x-1=0, x₁=-1/2, x₂=1
x²+x-2≠0, x₁≠-2, x₂≠1
y≠2
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Answers & Comments
Verified answer
2x²-x-1=0, x₁=-1/2, x₂=1
x²+x-2≠0, x₁≠-2, x₂≠1
y≠2