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DaryaDelReY
@DaryaDelReY
September 2021
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Решите неравенства:
а)[tex] \frac{1}{6}x \ \textless \ 5[/tex]
б)1-3x≤0
в)5(y-1,2)-4,6>3y+1
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Gviona
1) (1/6)x<5
x<30
2)1-3x<=0
-3x<=-1
3x>=1
x>=1/3
3)5(y-1,2)-4,6>3y+1
5y-6-4,6-3y>1
2y>1+6+4,6
2y>11,6
y>5,8
1 votes
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Answers & Comments
x<30
2)1-3x<=0
-3x<=-1
3x>=1
x>=1/3
3)5(y-1,2)-4,6>3y+1
5y-6-4,6-3y>1
2y>1+6+4,6
2y>11,6
y>5,8