Дана геометрическая прогрессия:
b1=-2[tex] \frac{1}{3} [/tex] , bn+1=3bn
Найдите b6
b1=-2[tex] \frac{1}{3} [/tex] , bn+1=3bn
Найдите b6
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b2=3*7/3=7
q=b2/b1=7:7/3=7*3/7=3
b6=b1*q^5
b6=7/3*243=7*81=567