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Вертеева
@Вертеева
July 2022
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Report
1) 2 cos60° + [tex] \sqrt{3
} [/tex] cos30°
2)5 sin30°-ctg45°
3)2 sin30° + 6 cos60°-4 tg45°
4)3 tg45° * tg60°
5)4 tg60° * sin60°
6)12 sin60° * cos60°
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Answers & Comments
nKrynka
Решение
1) 2 cos60° +
cos30° = 2*(1/2) +
√3*(√3/2) = 1 + 3/2 = 2,5
2)5 sin30°-ctg45° = 5*(1/2)*1 = 5/2 = 2,5
3)2 sin30° + 6 cos60°-4 tg45° = 2*(1/2) + 6*(1/2) - 4* 1 = 1 + 3 - 4 = 0
4)3 tg45° * tg60° = 1 * (
√3) = √3
5)4 tg60° * sin60° =
√3*(√3/2) = 3/2 = 1,5
6)12 sin60° * cos60° = 12*(
√3/2)*(1/2) = 3√3
1 votes
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Answers & Comments
1) 2 cos60° + cos30° = 2*(1/2) + √3*(√3/2) = 1 + 3/2 = 2,5
2)5 sin30°-ctg45° = 5*(1/2)*1 = 5/2 = 2,5
3)2 sin30° + 6 cos60°-4 tg45° = 2*(1/2) + 6*(1/2) - 4* 1 = 1 + 3 - 4 = 0
4)3 tg45° * tg60° = 1 * (√3) = √3
5)4 tg60° * sin60° = √3*(√3/2) = 3/2 = 1,5
6)12 sin60° * cos60° = 12*(√3/2)*(1/2) = 3√3