Решите пожалуйста сколько сможете 8 класс[tex] \frac{ x^{2}+3x}{(x-3) ^{2} } : ( \frac{3}{x+3} + \frac{ x^{2}+9 }{ x^{2}-9}- \frac{3}{3-x} )[/tex] A) ( ([tex] \frac{x+5y}{ x^{2}-5y } - \frac{x-5y}{ x^{2}-5y } ) : \frac{25 y^{2}- x^{2} }{5 y^{2} } [/tex]
Б) [tex]( \frac{a-2b}{ a^{2}+2ab } - \frac{a+2b}{ a^{2}-ab } ) : \frac{4 b^{2} }{4 b^{2}- a^{2} } [/tex]
Г) [tex]( \frac{C}{C-2} - \frac{C}{C+2} - \frac{ C^{2}+4 }{4- C^{2} } ) ( \frac{(2-C) ^{2} }{2c+c ^{2} } [/tex]
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Б) [tex]( \frac{a-2b}{ a^{2}+2ab } - \frac{a+2b}{ a^{2}-ab } ) : \frac{4 b^{2} }{4 b^{2}- a^{2} } [/tex]
Г) [tex]( \frac{C}{C-2} - \frac{C}{C+2} - \frac{ C^{2}+4 }{4- C^{2} } ) ( \frac{(2-C) ^{2} }{2c+c ^{2} } [/tex]
Д)
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x(x+3)/(x-3)² : ( (3(x-3) +x²+9 +3(x+3)) /(x -3)(x+3) ) =
x(x+3)/(x-3)² : ( ( x²+6x +9) /(x -3)(x+3) ) =x(x+3)/(x-3)² : ( ( x+3)² /(x -3)(x+3) ) =
x(x+3)/(x-3)² * (x -3)/(x+3) =x/(x-3).
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A) ( (x+5y)/(x² -5y)-(x-5y)/(x² -5y) )* 5y²/(25y² -x²) =50y³/(x² -5y)(25y² -x²) .
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Б) ( (a -2b)/a(a+2b) -(a+2b)/a(a-2b) ) * (4b² -a²)/4b² =
(((a-2b)² -(a+2b)² ) /a(a² - 4b²))* (4b² -a²)/4b² =( 8b/(4b² -a²)) )* (4b² -a²)/4b² = 2 / b.
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г) =( C/(C-2) -C/(C+2) +(C²+4)/(C² - 4) ) *(C-2)²/C(C+2) =
( C² +2C -C² +2C +C² +4)/(C-2)(C+2) ) *(C-2)²/C(C+2) =
( (C +2)²/(C-2)(C+2) ) * (C-2)²/C(C+2) =(C-2) / C. || 1 -2/C ||
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