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mirasimashev
@mirasimashev
July 2022
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[tex]1+2sin \frac{ \pi x}{3}=0 [/tex] если х (2; 4)
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kirichekov
Verified answer
1+2sin(πx/3)=0
2sin(πx/3)=-1
sin(πx/3)=-1/2
πx/3=(-1)^n *arcsin(-1/2)+πn, n∈Z
πx/3=(-1)^(n+1) *(π/6)+πn, n∈Z |:(π/3)
x=(-1)^(n+1) *(1/2)+3n, n∈Z
n=0. x=(-1)¹ *(1/2)+3*0. x=1/2 ∉(2;4)
n=1. x=(-1)²*(1/2)+3*1. x=3,5
n=2. x=(-1)³ *(1/2)+3*2. x=5?5∉(2;4)
ответ:
х=3,5
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Answers & Comments
Verified answer
1+2sin(πx/3)=02sin(πx/3)=-1
sin(πx/3)=-1/2
πx/3=(-1)^n *arcsin(-1/2)+πn, n∈Z
πx/3=(-1)^(n+1) *(π/6)+πn, n∈Z |:(π/3)
x=(-1)^(n+1) *(1/2)+3n, n∈Z
n=0. x=(-1)¹ *(1/2)+3*0. x=1/2 ∉(2;4)
n=1. x=(-1)²*(1/2)+3*1. x=3,5
n=2. x=(-1)³ *(1/2)+3*2. x=5?5∉(2;4)
ответ: х=3,5