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iromashka01
@iromashka01
July 2022
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Упростить выражение ([tex] \frac{t}{ t^{2}+2t+4 } [/tex] - [tex] \frac{ t^{2}+8 }{8- t^{3} } [/tex] - [tex] \frac{1}{t-2} [/tex]) × ([tex] \frac{ t^{2} }{ t^{2}-4 } [/tex] - [tex] \frac{2}{2-t} [/tex]) и найти его значение при t = -1,92
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sedinalana
Verified answer
1)t/(t²+2t+4)+(t²+8)/(t-2)(t²+2t+4)-1/(t-2)=(t²-2t+t²+8-t²-2t-4)/(t-2)(t²+2t+4)=
=(t²-4t+4)/(t-2)(t²+2t+4)=(t-2)²/(t-2)(t²+2t+4)=(t-2)/(t²+2t+4)
2)t²/(t-2)(t+2)+2/(t-2)=(t²+2t+4)/(t-2)(t+2)
3)(t-2)/(t²+2t+4)*(t²+2t+4)/(t-2)(t+2)=1/(t+2)
t=-1,92
1/(-1,92+2)=1/0,08=12,5
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Verified answer
1)t/(t²+2t+4)+(t²+8)/(t-2)(t²+2t+4)-1/(t-2)=(t²-2t+t²+8-t²-2t-4)/(t-2)(t²+2t+4)==(t²-4t+4)/(t-2)(t²+2t+4)=(t-2)²/(t-2)(t²+2t+4)=(t-2)/(t²+2t+4)
2)t²/(t-2)(t+2)+2/(t-2)=(t²+2t+4)/(t-2)(t+2)
3)(t-2)/(t²+2t+4)*(t²+2t+4)/(t-2)(t+2)=1/(t+2)
t=-1,92
1/(-1,92+2)=1/0,08=12,5