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remixonxd
@remixonxd
July 2022
2
7
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найдите координаты точек пересечения графиков функций:
y=[tex] \frac{2}{x} [/tex] и y=x+1
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Answers & Comments
hraky
Ответ в приложении ♡♤■□●○♡■□●
1 votes
Thanks 1
remixonxd
Спасибо
amin07am
Verified answer
2/x=x+1
x^2+x=2, причем х не равен 0
x^2+x-2=0
По Виета:
х1=-2
х2=1
у1=-2+1=-1
у2=1+1=2
Ответ: (-2;-1) и (1;2)
1 votes
Thanks 1
hraky
забыли у найти
amin07am
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Answers & Comments
Verified answer
2/x=x+1x^2+x=2, причем х не равен 0
x^2+x-2=0
По Виета:
х1=-2
х2=1
у1=-2+1=-1
у2=1+1=2
Ответ: (-2;-1) и (1;2)