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ghagha0
@ghagha0
July 2022
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[tex] \frac{1}{81} ^{cosx} =9 ^{2sin2x} [/tex]
как решать помогите
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sedinalana
Verified answer
3^(-4cosx)=3^4sin2x
-4cosx=4sin2x
8sinxcosx+4cosx=0
4cosx(2sinx+1)=0
cosx=0⇒x=π/2+πn,n∈z
sinx=-1/2⇒x=(-1)^(k+1)*π/6+πk,k∈z
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ghagha0
в ответах еще 3 корень есть -5пи/6+2пиэн
ghagha0
откуда он?
sedinalana
sinx=-1/2;x=-п/6+2Пn и х=-5П/6 +2Пn если не по общей формуле
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Answers & Comments
Verified answer
3^(-4cosx)=3^4sin2x-4cosx=4sin2x
8sinxcosx+4cosx=0
4cosx(2sinx+1)=0
cosx=0⇒x=π/2+πn,n∈z
sinx=-1/2⇒x=(-1)^(k+1)*π/6+πk,k∈z