[tex]( 1 + x ) ^{2}[/tex] (больше равно) 16 [tex]( 2x - 7 ) ^{2}[/tex] < 9. Created by sansahaste. algebra-ru

tex] < 9...

sansahaste @sansahaste

December 2021 1 18 Report

[tex]( 1 + x ) ^{2}[/tex] (больше равно) 16
[tex]( 2x - 7 ) ^{2}[/tex] < 9

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bb573878

Ответ:

Объяснение:

$(1+x)^2\geq 16;(1+x)^2-16\geq 0;(1+x)^2-4^2\geq 0\\\\(1+x+4)(1+x-4)\geq 0;(x+5)(x-3)\geq 0\\\\+++[-5]---[3]+++>x\\\\Otvet:x\in(-\infty;-5]\cup[3;+\infty)\\\\\\(2x-7)^2$

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DanilaKotov3619 Здраствуйте, bb573878! Вы случайно не разбираетесь в геометрии и мат анализе (1 курс универ) или теории вероятности?

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