tex]. Найдите сумму первых четырех ее членов...

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Последовательность задана формулой [tex] c_{n} [/tex]=[tex] 3n^{2} -10[/tex]. Найдите сумму первых четырех ее членов.

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$C_n=3n^2-10\\c_1+c_2+c_3+c_4-?\\\\c_1=3*1^2-10=3-10=-7\\c_2=3*2^2-10=3*4-10=12-10=2\\c_3=3*3^2-10=27-10=17\\c_4=3*4^2-10=48-10=38\\\\c_1+...+c_4=-7+2+17+38=50$

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