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Kotovsky54
@Kotovsky54
August 2022
1
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Помогите решить следующее неравенство:
abs( (x-1)/(2x-1) ) < 1
Решаю как систему [tex] \left \{ {{ \frac{x+1}{2x-1} \ \textless \ 1} \atop { \frac{x+1}{2x-1} \ \textgreater \ -1}} \right. [/tex], но с ответом не сходится.
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Gviona
(x-1)/(2x-1) <1
[(x-1)/(2x-1)] -1<0
[(x-1-2x+1)]/(2x-1)<0
-x/(2x-1) <0
x/(2x-1)>0
____+____(0)____-____(1/2)___+______
x e (-беск.; 0) U (1/2;+беск.)
1 votes
Thanks 1
Kotovsky54
Спасибо с ответом сошлось, я разобрался ура!
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Answers & Comments
[(x-1)/(2x-1)] -1<0
[(x-1-2x+1)]/(2x-1)<0
-x/(2x-1) <0
x/(2x-1)>0
____+____(0)____-____(1/2)___+______
x e (-беск.; 0) U (1/2;+беск.)