tex] Очень надо!!! Помогите пожалуйста!!!!...

July 2022 1 5 Report

Разложите на множители!!! Пожалуйста!!!!!!!!!
1.1) [tex]5a+5b-am-bm[/tex]
1) [tex]36m^{2} - 100n^{2} [/tex]
2) [tex]a^{2} +8a+16[/tex]
3) [tex]6m - mn -6 +n [/tex]
4) [tex](3b -5)^{2} -49[/tex]
5) [tex]121m^{2} -88mn+16n^{2} [/tex]
6) [tex](a-9)^{2} + 2(a-9) (a+4) + (a+4)^{2} [/tex]
Очень надо!!! Помогите пожалуйста!!!!

Answers & Comments

dtnth

Verified answer

$5a+5b-am-bm=(5a+5b)-(am+bm)=\\\\5(a+b)-m(a+b)=(5-m)(a+b)$

$36m^2-100n^2=4*9m^2-4*25n^2=\\\\4(9m^2-25n^2)=4((3m)^2-(5n)^2)=\\\\4(3m-5n)(3m+5n)$

$a^2+8a+16=a^2+2*a*4+4^2=(a+4)^2$

$6m-mn-6+n=(6m-mn)-(6-n)=\\\\m(6-n)-1*(6-n)=(m-1)(6-n)$

$(3b-5)^2-49=(3b-5)^2-7^2=\\\\(3b-5+7)(3b-5-7)=(3b+2)(3b-12)=3(3b+2)(b-4)$

$121m^2-88n+16n^2=\\\\(11m)^2-2*11m*4n+(4n)^2=(11m-4n)^2$

$(a-9)^2+2(a-9)(a+4)+(a+4)^2=\\\\((a-9)+(a+4))^2=(a-9+a+4)^2=(2a-5)^2$

2 votes Thanks 4

Answers & Comments

Verified answer

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