June 2022 1 6 Report
№1
2 sinx-√2=0
№2
cos [tex] \frac{x}{4} [/tex] = -[tex] \frac{ \sqrt{2} }{2} [/tex] 
№3
tg x=√3
№4
3ctgx= -1
№5
2 [tex] cos^{2} [/tex] - sinx+1=0
№6
[tex]tg^{2} [/tex] x +ctg=0
№7 Решить неравенство
sinx ≤ -[tex] \frac{1}{2} [/tex] по 1 окружности
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