сos([tex]\alpha-\pi [/tex])
sin([tex]-\alpha -\frac{3}{2} \pi [/tex])
помогите, как такое решать?
sin([tex]-\alpha -\frac{3}{2} \pi [/tex])
помогите, как такое решать?
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Cos(α - π) = - CosαSin(- α - 3π/2) = - Sin(3π/2 + α) = Cosα