[tex]\left \{ {{-x^2+16\ \textgreater \ =0} \atop {x(-x-6)\ \textless \ 0}} \right.[/tex]

Помогите
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.