August 2022 1 28 Report
[tex] \frac{6}{4 x^{2} -1} + \frac{3}{2x+1} = \frac{2}{2x-1} + 1 [/tex]

5x^4-12x^3+11x^2-12x+5=0

[tex] \sqrt{3x+1}- \sqrt{x-1}=2
[/tex]

При каких значениях параметра а уравнение 4x^2-ax+a-3=0 имеет только один корень?
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