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bibchik
@bibchik
June 2023
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10 Баллов
L=28[tex]\pi[/tex]
R=?
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Nullpo201
L = 2πR
R = L/2π = 28π/2π = 14 единиц изменения
3 votes
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tex]
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Answers & Comments
L = 2πR
R = L/2π = 28π/2π = 14 единиц изменения