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aleshaskovorodka
@aleshaskovorodka
July 2022
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[tex]2x^{2} - 4\sqrt{2}x+3=0[/tex]
Решить формулой квадратного уравнения.
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армения20171
2х²-4√2*х+3=0
Д=(4√2)²-24=16*2-24=32-24=8
х=(4√2±√8)/4=(4√2±2√2)/4
х1=(4√2+2√2)/4=6√2/4=3√2/2
х2=(4√2-2√2)/4=2√2/4=√2/2
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Answers & Comments
Д=(4√2)²-24=16*2-24=32-24=8
х=(4√2±√8)/4=(4√2±2√2)/4
х1=(4√2+2√2)/4=6√2/4=3√2/2
х2=(4√2-2√2)/4=2√2/4=√2/2