[tex] \sqrt{27+10 \sqrt{2} } [/tex] Решите плиз. Created by kerdbeere. algebra-ru

tex] Решите плиз...

July 2022 1 6 Report

[tex] \sqrt{27+10 \sqrt{2} }
[/tex]
Решите плиз

iknowthatyoufeelbro $\sqrt{27+10 \sqrt{2} } = \sqrt{5^{2} +2*5* \sqrt{2} +(\sqrt{2})^2}= \\ 
\sqrt{(5+\sqrt{2})^2} =|5+\sqrt{2}|=5+\sqrt{2}$

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kerdbeere Спасибо огромное