Найдите arcsin(sin[tex]\frac{92}{5} \pi [/tex])? С объяснением пжл
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irishkax1
Найдем сначала sin(99π/5)=sin((100π/5)-(π/5))= =sin(20π-(π/5))=sin(-π/5) По формуле имеем arcsin(sina)=a, при -(π/2)arcsin(sin(99π/5))=arcsin(sin(-π/5))= = -π/5
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=sin(20π-(π/5))=sin(-π/5)
По формуле имеем arcsin(sina)=a, при -(π/2)arcsin(sin(99π/5))=arcsin(sin(-π/5))=
= -π/5