July 2022 1 10 Report
Помогите вывести рекуррентное соотношение связывающее [tex]U_{n+1} [/tex] и [tex]U_{n} [/tex].


∑ [tex] (-1)^{n+1} [/tex] * x[tex] \frac{2n-1}{2n-1} [/tex] сравнить с sinx
n+1

Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.