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Saimon55
@Saimon55
July 2022
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Решить по формулам:
( [tex] \frac{1}{2} [/tex]B +2)[tex] ^{2} [/tex]
(4a-3B)[tex] ^{2} [/tex]
16B[tex] ^{4} [/tex] - 0,01
(Где [tex] ^{2} [/tex] и [tex] ^{4} [/tex] - степень)
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qwertyhappy54
(4a-3B)² = 16а³-2*4а*3b+9b² = 16a²+24ab+9b²
16B - 0,01 = (4b²- 0.1²) = 16
- 0.8 b + 0.01
( B +2) =
b² +4
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Answers & Comments
16B - 0,01 = (4b²- 0.1²) = 16 - 0.8 b + 0.01
( B +2) = b² +4