Home
О нас
Products
Services
Регистрация
Войти
Поиск
настек2
@настек2
September 2021
1
18
Report
[tex]9 ^{log _{3}4 } +log _{ \sqrt{6} } 3*log x_{3} 36[/tex] вычислить приводя к общему основанию
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
satko
=
16+log
√6
3 *(
2+log3 4)=
16+log3
√6
*(2+log3
4)=
16+2*log3
√6+
log3
√6 *
log3
4=
16+ 2*(log3
√3 + log3 √2)+ (log3 √3 +log3 √2)* log3
4=
16+2*(1/2 +
log3 √2) + (1/2+log3 √2)* log3 4=
17+ log3 √2 + 1/2*log3 4 + log3 √2 * log3 4=
17+ log3 √2 + 2*log3 √2 + 4*log3 √2*log3 √2=
17+3*log3 √2+4(log3 √2)^2
0 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tex] вычислить приводя к общему основанию..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
16+log√6 3 *(2+log3 4)=
16+log3 √6 *(2+log3 4)=
16+2*log3 √6+log3 √6 * log3 4=
16+ 2*(log3 √3 + log3 √2)+ (log3 √3 +log3 √2)* log3 4=
16+2*(1/2 + log3 √2) + (1/2+log3 √2)* log3 4=
17+ log3 √2 + 1/2*log3 4 + log3 √2 * log3 4=
17+ log3 √2 + 2*log3 √2 + 4*log3 √2*log3 √2=
17+3*log3 √2+4(log3 √2)^2