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настек2
@настек2
September 2021
1
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[tex]9 ^{log _{3}4 } +log _{ \sqrt{6} } 3*log x_{3} 36[/tex] вычислить приводя к общему основанию
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satko
=
16+log
√6
3 *(
2+log3 4)=
16+log3
√6
*(2+log3
4)=
16+2*log3
√6+
log3
√6 *
log3
4=
16+ 2*(log3
√3 + log3 √2)+ (log3 √3 +log3 √2)* log3
4=
16+2*(1/2 +
log3 √2) + (1/2+log3 √2)* log3 4=
17+ log3 √2 + 1/2*log3 4 + log3 √2 * log3 4=
17+ log3 √2 + 2*log3 √2 + 4*log3 √2*log3 √2=
17+3*log3 √2+4(log3 √2)^2
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Answers & Comments
16+log√6 3 *(2+log3 4)=
16+log3 √6 *(2+log3 4)=
16+2*log3 √6+log3 √6 * log3 4=
16+ 2*(log3 √3 + log3 √2)+ (log3 √3 +log3 √2)* log3 4=
16+2*(1/2 + log3 √2) + (1/2+log3 √2)* log3 4=
17+ log3 √2 + 1/2*log3 4 + log3 √2 * log3 4=
17+ log3 √2 + 2*log3 √2 + 4*log3 √2*log3 √2=
17+3*log3 √2+4(log3 √2)^2