Решите пожалуйста.
cos2x + [tex] \sqrt{2} [/tex] * sin ([tex] \frac{ \pi }{2} [/tex] +x) +1=0
cos2x + [tex] \sqrt{2} [/tex] * sin ([tex] \frac{ \pi }{2} [/tex] +x) +1=0
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2cos^2 x-1-v(2)cos x+1=0. 2cos^2 x-v(2)cos x=0. v(2)*cos x*(v(2)cos x-1)=0. 1)cos x=0, x=pi/2+pi*k. 2) v(2)cos x-1=0. cos x=1/v(2). x=+-pi/4+2pi*n