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trololowka20011
@trololowka20011
October 2021
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[tex] x^{2} [/tex] +x-6
2 [tex] x^{2} [/tex] -x-3
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pomoshnik09
1) х1=-3 х2=2 по т Виета легко подбирается
х²+х-6=(х+3)(х-2)
2) 2х²-х-3 найдем корни D=-1²-4*2*-3=1+24=25 x1=1+5)/4=1.5 x2=1-5x)/4=-1
2x²-x-3=2(x-1.5)(x+1)=(2x-3)(x+1)
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Answers & Comments
х²+х-6=(х+3)(х-2)
2) 2х²-х-3 найдем корни D=-1²-4*2*-3=1+24=25 x1=1+5)/4=1.5 x2=1-5x)/4=-1
2x²-x-3=2(x-1.5)(x+1)=(2x-3)(x+1)