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akhtulova02
@akhtulova02
July 2022
1
11
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Решите уравнение: [tex]121x+121-x^{3} -x^{2} =0[/tex]
x1=?
х2=?
х3=?
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witch2
Verified answer
121x + 121 - x^3 - x^2 = 0
121 (x+1) - x^2 (x+1) = 0
(121 - x^2) + (x+1) = 0
x+1 = 0 121 - x^2 = 0
x= - 1 121 = x^2 |: V
x = pljus/minus 11
otvet: x1 = -1 , x2 = -11 , x3 = 11
1 votes
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Answers & Comments
Verified answer
121x + 121 - x^3 - x^2 = 0121 (x+1) - x^2 (x+1) = 0
(121 - x^2) + (x+1) = 0
x+1 = 0 121 - x^2 = 0
x= - 1 121 = x^2 |: V
x = pljus/minus 11
otvet: x1 = -1 , x2 = -11 , x3 = 11