[tex] (\frac{1}{4a} + \frac{1}{5a}) \frac{ a^{2} }{9} [/tex] !знак умножения после скобок!. Created by Gyluzo. algebra-ru

tex] !знак умножения после скобок!...

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$(\frac{1}{4a} + \frac{1}{5a} )* \frac{a^2}{9} = \frac{5a+4a}{20a^2} * \frac{a^2}{9} = \frac{9a}{20a^2} * \frac{a^2}{9} = \frac{a}{20}$
общий знаменатель $20a^2$

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Gyluzo Спасибо, спасибо! The best!

sedinalana 1)1/(4а)+1/(5а)=(5+4)/(20а)=9/(20а)
2)9/(20а)*а²/9=а/20

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