Дано :
[tex] \cos( \alpha ) = \frac{ \sqrt{21} }{7} [/tex]
[tex] \ \sin( \beta ) = \frac{ 5\sqrt{7} }{14} [/tex]
0° < а < 90°
0° < B < 90°
Найти : а + B
[tex] \cos( \alpha ) = \frac{ \sqrt{21} }{7} [/tex]
[tex] \ \sin( \beta ) = \frac{ 5\sqrt{7} }{14} [/tex]
0° < а < 90°
0° < B < 90°
Найти : а + B
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