РЕШИТЕ УРАВНЕНИЕ! [tex](x^2+1)^2 - 6(x^2+1)^2+5=0[/tex]. Created by nekonii321. matematika-ru

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РЕШИТЕ УРАВНЕНИЕ!
[tex](x^2+1)^2 - 6(x^2+1)^2+5=0[/tex]

Answers & Comments

evgenrubalko11
$( { {x}^{2} + 1)}^{2} - 6( { {x}^{2} + 1)}^{2} + 5 = 0 \\ {x}^{4} + 2 {x}^{2} + 1 - 6({x}^{4} + 2 {x}^{2} + 1) + 5 = 0 \\ {x}^{4} + 2 {x}^{2} + 1 - 6 {x}^{4} - 12 {x}^{2} - 6 + 5 = 0 \\ - 5 {x}^{4} - 10 {x}^{2} + 0 = 0 \\ - 5 {x}^{2} \times ( {x}^{2} + 2) = 0 \\ {x}^{2} \times ( {x}^{2} + 2) = 0 \\ {x}^{2} = 0 \\ {x}^{2} + 2 = 0 \\ x = 0 \\$
x∉R
Ответ: x=0

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