Решите неравенство [tex] 0,5^{x^{2} - 4x} \leq 8[/tex]. Created by Pizzacat. algebra-ru

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July 2022 1 10 Report

Решите неравенство
[tex] 0,5^{x^{2} - 4x} \leq 8[/tex]

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sedinalana

Verified answer

(1/2)^x²-4x≥(1/2)^-3
x²-4x≥-3 основание меньше 1,знак меняется
x²-4x+3≥0
x1+x2=4 U x1*x2=3
x1=1 x2=3
+ _ +
---------------[1]--------------------[3]----------------
x∈(-∞;1] U [3;∞)

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