Решите систему уравнений:
[tex] \left \{ {{2x+y=1} \atop {3x^2-xy=18}} \right. [/tex]
[tex] \left \{ {{2x+y=1} \atop {3x^2-xy=18}} \right. [/tex]
More Questions From This User See All
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
3х^2-х+2х^2=18
5х^2-х-18=0
D=1+4•5•18=361>0
x1=(1+√361)/10=(1+19)/10=2
x2=(1-19)/10=-18/10=-9/5
y1=1-2x1=1-4=-3
y2=1-2x2=1-2(-9/5)=1+18/5=23/5
ответ (2;-3) (-9/5;23/5)